I want to shorten the conditions of a javascript if but I don't know how I can achieve it
code:
if ((!emailValidation() || (!nameValidation()) || (!surnameValidation()) || (!addressValidation()) || (!cityValidation()) || (!postalCodeValidation()))) {
}
I have the conditions defined in this way:
let surnameValidation = () => {
if (apellidoUsuario.value.length == 0) {
surnameError();
return false;
}
else if (apellidoUsuario.value.length == 1) {
surnameError();
return false;
}
else {
apellidoUsuario.focus;
apellidoUsuario.style.border = '0';
apellidoUsuario.style.backgroundColor = 'transparent';
apellidoUsuario.style.outline = '1px solid #00ffb1'
apellidoUsuario.style.transitionDuration = '0.4s'
return true;
}
I appreciate any help! :)
CodePudding user response:
You can remove all unnecessary parenthesis in your if
condition:
if (
!emailValidation() ||
!nameValidation() ||
!surnameValidation() ||
!addressValidation() ||
!cityValidation() ||
!postalCodeValidation()
) {
}
Other than that, there's not really a clean, readable way to shorten your code.
CodePudding user response:
Proposition #1:
I would probably get those validations into a variable or function:
validations() {
return [
emailValidation(),
nameValidation(),
surnameValidation(),
addressValidation(),
cityValidation(),
postalCodeValidation()];
}
and then I would:
if(validations().some(x=> !x)){
...
}
since validations return an array you can just use the some operator to find any invalid value.
Proposition #2:
I particularly would:
valid() {
return [
emailValidation(),
nameValidation(),
surnameValidation(),
addressValidation(),
cityValidation(),
postalCodeValidation()].every(x => x === true);
}
and then I would:
if(!valid()){
...
}
It is always cleaner to use true conditions on if statements instead of false ones.
References: Clean Code - Uncle Bob.