Replacing linefeeds but not \n in a variable (JavaScript)-CodePudding

In this case, I want to replace linefeeds(\n) to @ but not \n used inside the variable. Are there any ways to distinguish linefeeds from \n inside the code?

For example, I don't want to replace \n inside this: alert("abc \n cde")

let my_code = `
    alert("abc \n cde");
    alert("efd \n hij");
    alert("klm \n opq");
    alert("stu \n vwx");
`;
console.log( my_code )
my_code = my_code.replace(/\n/g, '@');
console.log( my_code )

online code editor: https://jsfiddle.net/r6La9mz2/

CodePudding user response：

"\n" is a line-feed. If you want to write \n (a backslash and an 'n') in a string, you have to write "\\n", and thus

console.log("abc \\n cde".replace(/\n/g, '@'));

will output

abc \n cde

CodePudding user response：

It is not possible. Once you use \n in string literal or string template it is parsed the same way you'd "pressed enter" there:

`#
#` === `#\n#` // true

In your particular use-case/example it may help to replace only all newlines not preceded by a space (/(?<! )\n/g) sequences, provided the "real" newlines are not also preceded by spaces.

`a \n b
c \n d`.replace(/(?<! )\n/g,'@') 
===
`a 
 b@c 
 d` // true