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For help! Unicode high replacement, low how to do?

Time:10-06

I from a 犇 Unicode website know
 
The Universal Character Set USES surrogates to
The address characters outside the initial Basic
Multilingual Plane
Without resorting to wining 16 bit byte
2048 surrogate representations. By combining pairs of the
Code points, and the remaining characters in
All the other planes can be
Addressed (1024 x 1024=
1048576 code points in the other 16 planes).
In this way, UCS has a built - In 16 bit encoding
Capability for
UTF - 16. These code points are no means
Into leading or high "surrogates"
(D800 - DBFF) and trailing or
"Low surrogates"
(DC00 - DFFF) In UTF - 16,
They must always appear in pairs,
As a high surrogate followed
By a low surrogate, thus using 32 bits to
Denote one code point.

How it use in Unicode?

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CodePudding user response:

I'll real-time points
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