# include 

Int main (void) 
{
Int a, b; 

Puts (" both Please input two integers: "); 
Printf (" Integer a: "); The scanf (" % d ", & amp; A); 
Printf (" Integer b: "); The scanf (" % d ", & amp; b); 

Printf (" The result is: % f. \ n ", (a + b)/2); 

return 0; 
} 

The final output statements, the output is 0; Change 2 to 2.0, you can output, 3.000000
Why is zero divisor is 2 output?

Thank you very much!

CodePudding user response:

Printf (" The result is: % f. \ n ", (a + b)/2); Integer in addition to the results or integer, use % f output shows a 0
After 2 to 2.0 in addition to the result is floating point Numbers, use % f output can show the correct value

CodePudding user response:

Undefined behavior results without discussion there are many different possible