How do I make a working if statement that repeats on if false in Python?-CodePudding

name = input("What is your name?\n")

menu = "Black Coffee", "Espresso", "Latte", "Cappucino","Frappuccino"

while True:
   order = input(name   ", what would you like from our menu today? Here is what we are serving.\n")
   if order == "Black Coffee":
       print("Thank you.")
   elif order == "Espresso":
        print("Thank you.")
   elif order == "Latte":
        print("Thank you.")
   elif order == "Cappucino":
        print("Thank you.")
   elif order == "Frappucino":
        print("Thank you.")
   else:
       print("play again.. etc...")

quantity = input("How many "   order   "s would you like?\n")

total = price * int(quantity)

total_time = int(quantity) * time

print("Thank you. Your total is: $"   str(total))

print("Sounds good "   name   ", we will have your "   quantity   " "  order   " ready for you in "   str(total_time)   " min.")

I am a guy who is a beginner in Python. I have a problem with my code that when I enter for example "Latte" It will say "Thank you." and it jumps back and says "name , what would you like from our menu today? Here is what we are serving.". I do not want that to happen, instead I want it to say the line under it (How many " order "s would you like?). Also, when I add the variable "menu" to my "order" variable (in the string) it says "can only concatenate str (not "tuple") to str" I would really appreciate your help.

CodePudding user response：

Use the break keyword to break out of the while loop:

while True:
   order = input(name   ", what would you like from our menu today? Here is what we are serving.\n")
   if order in menu:
       print("Thank you.")
       break
   else:
       print("play again.. etc...")