, please help me!!!!!!!!!!!!
The original https://pintia.cn/problem-sets/994805260223102976/problems/994805323154440192
My code

 # include & lt; Iostream> 

using namespace std; 

Int main (void) 
{
int n; 
Cin> & gt; n;//-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- input n 
for(int i=0; i{
Cin. Sync (); 
Cin. The clear ();//-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- empty buffer 
Int a=0, b=0, c=0, * flag, cp=0, ct=0;//-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- the third rule in the topic, with a, b, c three int to store a number of different position, number of cp, cp is used to record the T, P 
Flag=& amp; a;//-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- initialized flag pointer to a (starting from a 
Char t;//-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- 
 temporary variablesWhile ((t=cin. The get ())!=(EOF) 
{
If (t! 
='A'){
If (t=='P' & amp; & (! Cp)) 
{
Flag=& amp; b; 
Cp++; 
}//-- -- -- -- -- -- -- -- -- -- -- -- -- -- when read into P, that a string has been finished, at this time would hand flag to point b, after start reading b string in a number of 
The else 
{
If (t=='t' & amp; & (! Ct) & amp; & Cp) 
{
Flag=& amp; C; 
Ct++; 
}//-- -- -- -- -- -- -- -- -- -- when read again after reading P T, b series has been finished, at this time would hand flag to point c, then start reading c string in A number of 
The else 
{
If (t=='\ n') 
If (c==b * a& & b> 0 & amp; & Cp==ct& & Cp==1)//if the newline character and meet the conditions, the output YES 
Cout<" YES "& lt; The else 
Cout<" NO "& lt; The else 
Cout<" NO "& lt; break; 
} 
} 

} 
The else 
(* flag) + +;//-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- if you have read is A, will be the flag Pointers int++, on behalf of A, b, c to each string contains A number of 
} 
} 
return 0; 
} 

0 points, all the answers wrong, but don't know what the problem is, help sigh agghh ~

CodePudding user response:

The top

CodePudding user response:

Wrong rules, natural all wrong ~ ~ ~ the PTA, when...

 
#include 
#include 

Int main () {
Int n, I, j; 
Int CNTP=0, CNTT=0, CNTA=0, flag=1; 

P1, char * * p2. 
The scanf (" % d ", & amp; N); 
Char s [10] [100]. 
for(i=0; iThe scanf (" % s ", s [I]); 

for(i=0; i{
Flag=1; 
CNTP=CNTA=CNTT=0; 
//count P, A, the number of T, if you have other characters NO; Rules of [1] 
for(j=0; S [I] [j].='\ 0'; J++) 
{
If (s [I] [j]=='P') cntp++; 
Else if (s [I] [j]=='A') cnta++; 
Else if (s [I] [j]=='T') cntt++; 
The else {flag=2; break; } 
} 
//there is only 1 P and T, at least 1 A; Rules of [2] 
If (flag==1 & amp; & CNTP==1 & amp; & CNTT==1 & amp; & CNTA!=0) 
{
P1=STRCHR (s [I], "P"); 
P2=STRCHR (s [I] 'T'); 
//aPbATca refers to: (A number) in front of the P * (P T between A number of)==T behind A number of; [3] 
If ((p1 - s [I]) * (p2 - p1-1)==strlen (p2) - 1) 
flag=0; 
} 
If (flag==0) puts (" YES "); 
The else puts (" NO "); 
} 
return 0; 
}