I'd like to parse the following look up table as follows:
I want to check the branch name and fetch the corresponding name value, but i want to do fetch first name of each branch, like:
[branch: "test"] => name "a"
then [branch: "test-1"] => name "d"
and so on.
LUT = [
[branch: "test", name: 'a', image_name: 'abc'],
[branch: "test", name: 'b', image_name: 'abc'],
[branch: "test", name: 'c', image_name: 'abc'],
[branch: "test-1", name: 'd', image_name: 'abc'],
[branch: "test-1", name: 'e', image_name: 'abc'],
[branch: "test-2", name: 'f', image_name: 'abc'],
[branch: "test-2", name: 'g', image_name: 'abc'],
[branch: "test-2", name: 'h', image_name: 'abc'],
[branch: "test-3", name: 'i', image_name: 'abc'],
[branch: "test-3", name: 'j', image_name: 'abc'],
[branch: "test-4", name: 'k', image_name: 'abc'],
[branch: "test-5", name: 'l', image_name: 'abc'],
]
for example the result may look like:
result = {
"test": [{ "name":"a" }],
"test-1": [{ "name":"d" }],
"test-2": [{ "name":"f" }],
"test-3": [{ "name":"i" }],
"test-4": [{ "name":"k" }],
"test-5": [{ "name":"l" }],
}
Also, I might like to add additional values to the keys for example in test-1:
"test-1": [{ "name": "a", "new_name": "new" }]
CodePudding user response:
Not positive how to format the result like you want it but finding the first instance of each branch is fairly easy.
result = [:]
for (map in LUT)
{
if (!result.containsKey(map['branch']))
{
println map['name'] // prints the unique name
result.put(map['branch'], map['name'])
}
}
CodePudding user response:
I'm not sure about your curly brackets, but this creates a map:
def original = [
[branch: "test", name: 'a', image_name: 'abc'],
[branch: "test", name: 'b', image_name: 'abc'],
[branch: "test", name: 'c', image_name: 'abc'],
[branch: "test-1", name: 'd', image_name: 'abc'],
[branch: "test-1", name: 'e', image_name: 'abc'],
[branch: "test-2", name: 'f', image_name: 'abc'],
[branch: "test-2", name: 'g', image_name: 'abc'],
[branch: "test-2", name: 'h', image_name: 'abc'],
[branch: "test-3", name: 'i', image_name: 'abc'],
[branch: "test-3", name: 'j', image_name: 'abc'],
[branch: "test-4", name: 'k', image_name: 'abc'],
[branch: "test-5", name: 'l', image_name: 'abc'],
]
println original
.groupBy { branch -> branch.branch }
.collectEntries { key,value -> [(key) : [name : value.get(0).name]] }