I have the following dataset
structure(list(Var1 = structure(c(1L, 2L, 1L, 2L, 1L, 2L, 1L,
2L), .Label = c("0", "1"), class = "factor"), Var2 = structure(c(1L,
1L, 2L, 2L, 1L, 1L, 2L, 2L), .Label = c("congruent", "incongruent"
), class = "factor"), Var3 = structure(c(1L, 1L, 1L, 1L, 2L,
2L, 2L, 2L), .Label = c("spoken", "written"), class = "factor"),
Freq = c(8L, 2L, 10L, 2L, 10L, 2L, 10L, 2L)), class = "data.frame", row.names = c(NA,
-8L))
I would like to add another column reporting sum of coupled subsequent rows. Thus the final result would look like this:
I have proceeded like this
Table = as.data.frame(table(data_1$unimodal,data_1$cong_cond, data_1$presentation_mode)) %>%
mutate(Var1 = factor(Var1, levels = c('0', '1')))
row = Table %>% #is.factor(Table$Var1)
summarise(across(where(is.numeric),
~ .[Var1 == '0'] .[Var1 == '1'],
.names = "{.col}_sum"))
column = c(rbind(row$Freq_sum,rep(NA, 4)))
Table$column = column
But I am looking for the quickest way possible with no scripting separated codes. Here I have used the dplyr package, but if you might know possibly suggest some other ways with map(), for loop, and or the method you deem as the best, please just let me know.
CodePudding user response:
This should do:
df$column <-
rep(colSums(matrix(df$Freq, 2)), each=2) * c(1, NA)
CodePudding user response:
If you are fine with no NAs
in the dataframe, you can
df %>%
group_by(Var2, Var3) %>%
mutate(column = sum(Freq))
# A tibble: 8 × 5
# Groups: Var2, Var3 [4]
Var1 Var2 Var3 Freq column
<fct> <fct> <fct> <int> <int>
1 0 congruent spoken 8 10
2 1 congruent spoken 2 10
3 0 incongruent spoken 10 12
4 1 incongruent spoken 2 12
5 0 congruent written 10 12
6 1 congruent written 2 12
7 0 incongruent written 10 12
8 1 incongruent written 2 12