Delete specific duplicated punctuation from string-CodePudding

I have this string s = "(0|\\ 33)[1-9]( *[0-9]{2}){4}". And I want to delete just the duplicated just one ' \ ', like I want the rsult to look like (0|\ 33)[1-9]( *[0-9]{2}){4}.

When I used this code, all the duplicated characters are removed: result = "".join(dict.fromkeys(s)).

But in my case I want just to remove the duplicated ' \ '. Any help is highly appreciated

CodePudding user response：

The function you need is replace

s = "(0|\\ 33)[1-9]( *[0-9]{2}){4}"
result = s.replace("\\","")

EDIT

I see now that you want to remove just one \ and not both. In order to do this you have to modify the call to replace this way

result = s.replace("\","",1) # last argument is the number of occurrances to replace

result = s.replace("\\","\")

EDIT of the EDIT

Backslashes are special in Python.

I'm using Python 3.10.5. If I do

x = "ab\c"
y = "ab\\c"
print(len(x)==len(y))

I get a True. That's because backslashes are used to escape special characters, and that makes the backslash a special character :) I suggest you to try a little bit with replace until you get what you need.

CodePudding user response：

A solution using the re module:

import re
s = r"(0|\\ 33)[1-9]( *[0-9]{2}){4}"
s = re.sub(r"\\(?=\\)", "", s)
print(s)

I look for all backslashes, that are followed by another backslash and replace it with an empty sign.

Output: (0|\ 33)[1-9]( *[0-9]{2}){4}