I want to create elements of a list where each element comes from a satisfied nested for if loop sta-CodePudding

str1 ="John000Doe000123"

list1 = []

for i in str1:
  if i == "0":
    continue
    
  
  list1.append(i)

print(list1)

OUTPUT: ['J', 'o', 'h', 'n', 'D', 'o', 'e', '1', '2', '3']

but the output that I want is:

OUTPUT: ['John' , 'Doe' , '123']

CodePudding user response：

You could split your string at character '0' and seek only valid entries from there:

str1 ="John000Doe000123"

print([name for name in str1.split('0') if name])
# ['John', 'Doe', '123']

CodePudding user response：

One of the simple solution using loop will be:

str1 ="John000Doe000123"

list1 = []
str2 = ""

for i in str1:
  if i == "0":
    if str2!="":
        list1.append(str2)
        str2 = ""
  else:
      str2  = i

if str2!= "":
    list1.append(str2)

print(list1)

CodePudding user response：

Just to cover all the splitting options, you can also do this with regular expressions to split on variable length sequences of "0":

>>> import re
>>> re.split(r"0 ", str1)
['John', 'Doe', '123']

(in this case it's not necessary to use a raw string but it's a good habit for regexes)

CodePudding user response：

Quick and easy, you want s.split('000').

For variable number of 0's, use a regex solution as mentioned by other answer.

>>> str1 ="John000Doe000123"
>>> str1.split('000')
['John', 'Doe', '123']