Avoid calling a function twice-CodePudding

I have the following situation in Python:

def func_0(x):
    '''takes x as a numpy array'''
    # connects to a third party software
    val_1, val_2 = output_extracted_from_a_third_party_software
    return [val_1, val_2]

def func_1(x):
    return func_0()[0]

def func_2(x):
    return func_0()[1]

another_third_party_func(func_1, func_2) # this is a function that I cannot modify

Facts:

It is not possible for me to modify func_0 because it just extracts the output of a third party software (a computationally expensive process).
As a part of an algorithm, I have to pass func_1 and func_2 as 2 separate arguments into another third party library.

I'm looking for a more efficient way to define func_1 and func_2, so that I avoid calling func_0 twice.

Thank you in advance.

EDIT: Memorization doesn't work in this case because x has to be a numpy array.

CodePudding user response：

you can use memoization to solve this ... i think just the builtin LRU cache would work

@functools.lru_cache
def func_0(x):
    do something using x
    return [val_1, val_2]

of coarse this only works if x is the same in both calls ...

you can see it work as follows

import functools

@functools.lru_cache
def func_0(x):
    print("do something using x")
    return [x,x 1]

print(func_0(5)) # see print 'about do something using x'
print(func_0(6)) # see print 'about do something using x'
print(func_0(5)) # DO NOT see print 'about do something using x'

CodePudding user response：

Could you be looking for Tuple unpacking?