this is my code below and please help me find out the the expected output[ 4,5,6,0,0,0]
def movel(s, k):
n=len(s)
j=0
n_arr=s[:k]
return (s[k::] n_arr[::])
for j in range(0, n):
print(s[j], end=' ')
s=[1,2,3,4,5,6]
k=3
movel(s,k)
*Output : [4,5,6,1,2,3] *
CodePudding user response:
You could do use index slicing
def movel(s, k):
if k > len(s):
return [0] * len(s) # you decide how to handle this case
return s[k:] [0] * (len(s) - k)
Think of it this way, we change the head of the list and fill the rest with zeros.