Creating datetime series in python-CodePudding

I have a recording with the start time (t0) and length of the recording (N). How do I create a time series vector (ts) in python for every 10s increments?

For example: 
t0 = 2017-06-12T11:05:10.00
N=1000
So there should be an array of 100 (N/10)values such that: 
ts = [2017-06-12T11:05:10.00, 2017-06-12T11:05:20.00,2017-06-12T11:05:30.00 and so on...]

CodePudding user response：

import datetime
import numpy as np

t0=datetime.datetime(2017, 6, 12, 11, 5, 10)
dt=datetime.timedelta(seconds=10)
ts=np.arange(100)*ts t0

There might be some easier way. I've never tried to find one. But this is how I do it.

CodePudding user response：

You can use the datetime module of Python. First you need to convert your string into a date with dateteime.strptime:

t0 = datetime.datetime.strptime("2017-06-12T11:05:10.00", "%Y-%m-%dT%H:%M:%S.00")

where the "%Y-%m-%dT%H:%M:%S.00" part is the description of your string format (see documentation)

Then you can increment a datetime object by adding a timedelta to it. Build a sequence like this:

delta = datetime.timedelta(seconds=10)
ts = [t0   i*delta for i in range(N)]

You can also recover dates as strings by using datetime.strftime with a similar syntax to strptime.

The whole thing would look like

from datetime import datetime, timedelta

date_format = "%Y-%m-%dT%H:%M:%S.00"
t0 = datetime.strptime("2017-06-12T11:05:10.00", date_format)
delta = timedelta(seconds=10)
ts = [datetime.strftime(t0   i * delta, date_format) for i in range(100)]