Return words from a list that dosen't contain the same words-CodePudding

Hey (sorry bad english) so let me explain a little further. i want to make a function that takes in a list. let's say a list with a countries and their capital also added their population. i want to return every country-capital pair that dosen't contain the same letter. like this:

countries = [
    ["China PR", "Beijing", 20693000],
    ["India", "New Delhi", 16787949],
    ["Japan", "Tokyo", 13491000],
    ["Philippines", "Manilla", 12877253],
    ["Russia", "Moscow", 11541000],
    ["Egypt", "Cairo", 10230350]
]
#the output should be:
>>> no_common_letters(countries)
[["Japan", "Tokyo"], ["Egypt", "Cairo"]]

because Japan and Tokyo dosen't contain the same letters. anyone know a sulotion to this? i have tried looking around and all i can find is a program that finds a specified letter and check's if it's in. i want to check every word. i am new to python and trying to learn

CodePudding user response：

You can use this code:

def no_common_letters(array_of_arrays):
    new_array = []
    for array in array_of_arrays:
        determination = []
        for x in array[0]:
            if x not in array[1]:
                determination.append('1')
            else:
                determination.append('0')
        if '0' not in determination:
            new_array.append(array[0:2])

    return new_array

print(no_common_letters([
    ["China PR", "Beijing", 20693000],
    ["India", "New Delhi", 16787949],
    ["Japan", "Tokyo", 13491000],
    ["Philippines", "Manilla", 12877253],
    ["Russia", "Moscow", 11541000],
    ["Egypt", "Cairo", 10230350]
]))


Returns 
>> [["Japan", "Tokyo"], ["Egypt", "Cairo"]]

OR using SETS

def no_common_letters(array_of_arrays):
  new_array = []
  for array in array_of_arrays:
    set1 = set(array[0])
    set2 = set(array[1])
    if not set1.intersection(set2):
      new_array.append(array[0:2])
  return new_array
print(no_common_letters([
    ["China PR", "Beijing", 20693000],
    ["India", "New Delhi", 16787949],
    ["Japan", "Tokyo", 13491000],
    ["Philippines", "Manilla", 12877253],
    ["Russia", "Moscow", 11541000],
    ["Egypt", "Cairo", 10230350]
]))



Returns 
>> [["Japan", "Tokyo"], ["Egypt", "Cairo"]]

CodePudding user response：

you can use set intersection method to filter:

In [2]: [[i[0], i[1]] for i in countries if not set(i[0].lower()).intersection(set(i[1].lower()))]
Out[2]: [['Japan', 'Tokyo'], ['Egypt', 'Cairo']]

CodePudding user response：

I think you can try with set

for x,y,_ in countries:
  if not set(x.lower()).intersection(y.lower()):
    print(x,y)