Trying to convert tuple to a dictionary and after that looking for the smallest item that contains a-CodePudding

So I was toying around with this code:

def cheapest_shark(prices: List, sharks: List ) -> Tuple:
    shp = zip(sharks, prices)
    sharkprices = tuple(shp)
    
    print(sharkprices)

My input is

cheapest_shark([230, 180, 52, 390, 520], [1, 0, 0, 1, 1])

(Each number is connected to each other in the output: (230, 1) (180, 0) etc, etc.)

I am trying to make the function in such a way that it always returns me the smallest item in the tuple (but it needs to have a 1 in it). So in this case the output needs to be (230,1). I tried converting it to a dict and then making a for loop which checks if there is a 1 as a value and then takes the lowest sum of the remaining items but that did not work out for me. Does anyone have any suggestions on how I could make this function work?

CodePudding user response：

Try to filter the tuples (keep only values where the shark is 1) and use min():

def cheapest_shark(prices, sharks):
    shp = ((p, s) for p, s in zip(prices, sharks) if s == 1)
    return min(shp, default=None)


x = cheapest_shark([230, 180, 52, 390, 520], [1, 0, 0, 1, 1])
print(x)

Prints:

(230, 1)

Note: If there isn't any tuple with value 1 the default= value is returned (in this case None). Without default= parameter the exception is thrown.