I am doing a kind of VLOOKUP operation in a column with about 3K cells. I am using the following function to do it. I commented on what the code is doing in the function, but to summarize:
- It creates a map from values to search for from a table with metadata
- It iterates each value of a given range, and searches for coincidences in the previous map
- If coincidences are found, it uses the index to capture the second column of the metadata table
- Finally, sets the value captured in another cell
This is the code:
function questions_categories() {
var ss = SpreadsheetApp.getActive();
var sheet = ss.getSheetByName("data_processed");
// get metadata. This will work as the table to look into
// Column B contains the matching element
// Column C contains the string to return
var metadata = ss.getSheetByName("metadata").getRange('B2:C').getValues()
// Just get the different values from the column B
var dataList = metadata.map(x => x[0])
// Used to define the last cell where to apply the vlookup
var Avals = sheet.getRange("A1:A").getValues();
var Alast = Avals.filter(String).length;
// define the range to apply the "vlookup"
const questions_range = sheet.getRange("Q2:Q" Alast);
forEachRangeCell(questions_range, (cell) => {
var searchValue = cell.getValue();
// is the value to search in the dataList we defined previously?
var index = dataList.indexOf(searchValue);
if (index === -1) {
// if not, throw an error
throw new Error('Value not found')
} else {
// if the value is there, use the index in which that appears to get the value of column C
var foundValue = metadata[index][1]
// set the value in two columns to the right
cell.offset(0, 2).setValue(`${foundValue}`);
}
})
}
forEachRangeCell()
is a helper function to iterate through the range.
This works very well, but it resolves 3-4 cells per second, which is not very efficient if I need to check thousands of data. I was wondering if there is a more performant way to achieve the same result.
CodePudding user response:
To improve performance, use Range.setValues()
instead of Range.setValue()
, like this:
function questions_categories() {
const ss = SpreadsheetApp.getActive();
const source = { values: ss.getRange('metadata!B2:C').getValues() };
const target = { range: ss.getRange('data_processed!Q2:Q') };
source.keys = source.values.map(row => row[0]);
target.keys = target.range.getValues().flat();
const result = target.keys.map(key => [source.values[source.keys.indexOf(key)]?.[1]]);
target.range.offset(0, 2).setValues(result);
}