Feel a c + + to do less, many will not, want a better resolve problem set point in detail, strives for the bosses to recommend, thank you
CodePudding user response:
Don't have to book, a lot of brush site PTA, LeetCode, valley, and, as for the search
CodePudding user response:
Reading and I think there's not much use (informatics orsay a general version of the c + +), the title is good, but, not necessarily can read, understand, would not necessarily write write not to, this is very troublesome, I can recommend according to the upstairs said, to brush the topic on the platform, to solve the problem. Every problem has a correctness verification, such practice would be high efficiency
CodePudding user response:
refer to the second floor Italink response: I think there's not much use, reading (informatics orsay, a general version of the c + +), the title is good, but, not necessarily can read, understand, would not necessarily write write not to, this is very troublesome, I can recommend according to the upstairs said, to brush the topic on the platform, to solve the problem. Every problem has a correctness verification, such practice would be high efficiency Oh oh, brush the topic platform... But no answer CodePudding user response:
reference 1st floor qq_45798109 response: don't have to book, a lot of brush site PTA, LeetCode, valley, and, as for the answer search Oh, oh, come back to search, thank you for your bosses is recommended CodePudding user response:
Can be found online to answer CodePudding user response:
reference 5 floor fireyou reply: can be found online to answer Online answer is a bit messy... CodePudding user response:
To answer questions can be asked here CodePudding user response:
The reference 7 floor fireyou response: to answer questions can be asked here Oo, okay, thank you CodePudding user response:
The reference 7 floor fireyou response: to answer questions can be asked here #include using namespace std; Int main () {int a [10], b [10], I; Cin> A, [10]. for(i=0; i<=9; I++) B [9 - I]=[I]; for(i=0; i<=9; I++) Cout return 0; } bosses you look at the right CodePudding user response:
Note that the code format,,, First a [10] this is crossing the line, and the array subscript starting from 0, #include using namespace std; Int main () { Int a [10], [10], b I; For (I=0; i <10; I++) { cin> A, [I]. } For (I=0; i <=9; I++) { B [9 - I]=[I]; } For (I=0; i <=9; I++) { cout } system("pause"); return 0; } CodePudding user response:
I just under the self-study, just saw information, thank you for your bosses CodePudding user response:
This is... Where can adopt point CodePudding user response:
Stick to the points, computer login, CodePudding user response:
Sorry ah, I use a mobile phone version of CodePudding user response:
On the computer log in BBS,, If don't have a computer, and suggest to give up programming, On the 14th floor qq_45829108 reference response: sorry ah, I use a mobile phone version of CodePudding user response:
,,,,,,,,,,,,,,, CodePudding user response:
You can go to los valley, to solve the problem. Basic all subject is the antithesis of, will not do it can refer to, and los valley also has carried on the classification on the theme, or better CodePudding user response:
Still need to practice more