I have created some code to search through a string and return True if there is an emoji in the string. The strings are found in a column in a pandas dataframe, and one can assume the string and the length of the dataframe could be arbitrarily long. I then create a new column in my dataframe with these boolean results.
Here is my code:
import emoji
contains_emoji = []
for row in df['post_text']:
emoji_found = False
for char in row:
if emoji.is_emoji(char):
emoji_found = True
break
contains_emoji.append(emoji_found)
df['has_emoji'] = contains_emoji
In an effort to get slicker, I was wondering if anyone could recommend a faster, shorter, or more pythonic way of searching like this?
CodePudding user response:
Use emoji.emoji_count()
:
import emoji
# Create example dataframe
df = pd.DataFrame({'post_text':['