Javascript - Use elements in array to filter array of objects-CodePudding

I am trying to filter an array of objects, based on the elements within another array.

The array of objects I would like filtered is:

const data = [
{id: 1, method: "bike"},
{id: 2, method: "walk"},
{id: 3, method: "bus"},
{id: 4, method: "bike"},
{id: 5, method: "walk"},
{id: 5, method: "bus"},
]

I have one of three arrays that have what method I would like to include

const filter1 = ['bike'];
const filter2 = ['bike', 'walk'];
const filter3 = ['bike', 'walk', 'bus'];

I am able to push the filtered array to a new array, but I would like the filtered array to have the same structure as data, instead of an array of arrays.

This is my current method, and it gives me a 2D array:

let output = [];
const filterArr = filter2.forEach(element => {
 const filt = data.filter(el => el.method === element);
 output.push(filt);
});

My desired output is:

const want = [
    {id: 1, method: "bike"},
    {id: 2, method: "walk"},
    {id: 4, method: "bike"},
    {id: 5, method: "walk"},
]

CodePudding user response：

I would convert the filter Array to a Set, and use the Set.prototype.has method to check if the current item's method exists within it.

const filter2 = new Set(['bike', 'walk']);

const data = [
  { id: 1, method: "bike" },
  { id: 2, method: "walk" },
  { id: 3, method: "bus"  },
  { id: 4, method: "bike" },
  { id: 5, method: "walk" },
  { id: 5, method: "bus"  },
];

const filtered = data.filter(({ method }) => filter2.has(method));

console.log(filtered);

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CodePudding user response：

You could take a filter array as methods and check if the method of the data array is included in the filter array.

methods = filter2, // one of your filters.
result = data.filter(({ method }) => methods.includes(method));