HANDLE h = HeapCreate(HEAP_GENERATE_EXCEPTIONS, 1024, 4096);
int* test = (int*)HeapAlloc(h, HEAP_GENERATE_EXCEPTIONS, sizeof(int));
__try {
HeapFree(h, 0, ((char*)test));
HeapFree(h, 0, ((char*)test));
}
__except (EXCEPTION_EXECUTE_HANDLER)
{
cout << "i want to get here";
}
new / delete can print message, why HeapAlloc is not? ( how to handle HeapAlloc double free error?)
CodePudding user response：
Structured Exception Handling doesn't work in this case.
Minimal example using a Vectored exception handler:
#include <Windows.h>
LONG NTAPI ExceptionHandler(PEXCEPTION_POINTERS p)
{
switch (p->ExceptionRecord->ExceptionCode)
{
case STATUS_HEAP_CORRUPTION:
// Do stuff
/* Continuing after this can be dangerous.
It is better to return EXCEPTION_CONTINUE_SEARCH
or directly terminate the program. */
return EXCEPTION_CONTINUE_EXECUTION;
}
return EXCEPTION_CONTINUE_SEARCH;
}
int main()
{
AddVectoredExceptionHandler(0, ExceptionHandler);
HANDLE h = HeapCreate(0, 1024, 4096);
LPVOID pv = HeapAlloc(h, 0, 42);
HeapFree(h, 0, pv);
HeapFree(h, 0, pv);
return 0;
}