javascript method for this challenge?-CodePudding

I'm doing this javascript algorithm challenge which has this array ['cat', 'game', 'socks'] and the function must return me this result:

[
  "******cat******",
  "*******game*******",
  "********socks********"
]

(each word has a * more than the previous word, so not all words should be equal), Would you use forEach? or how would you do it?

CodePudding user response：

We can do it via Array.map() and String.repeat()

let data = ['cat', 'game', 'socks']

let result = data.map((d,i) => {
  let s = `*`.repeat(i)
  let e = `*****${s}\n*${d}*\n${s}*****`
  return e
})

console.log(result)

CodePudding user response：

I was not going to originally submit an answer, but why not.

My approach would be using a for loop to iterate the list once and maintaining a string that gets incremented with a * for every for call.

In big-o notation, this would be an O(n) solution.

let data = ['cat', 'game', 'socks']
let buffer = '*****';

for(let i = 0; i < data.length; i  ) {
  data[i] = `${buffer}\n*${data[i]}*\n${buffer}`;
  buffer  = '*';
}

console.log(data)