Time:10-13
CodePudding user response:
select * from table name where tag_id=8 or tag_id=4
SELECT Eight. Id, Eight courseid, Eight. Tag_id The FROM (SELECT * The FROM The table name WHERE Tag_id=8 Eight) The JOIN (SELECT * The FROM The table name WHERE Tag_id=4 ) four ON eight. Courseid=four. Courseid
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