I have a lottery game where I can generate 1 set of 6 numbers.I am trying to generate two sets of 6 numbers but am unable to do so.

        public static void LottoDraw()
        {
            int[] lotto = new int[6];
            Random LottoNumbers = new Random();

            for (int i = 0; i < lotto.Length; i  )
            {
                lotto[i] = LottoNumbers.Next(1, 47);
            }
            Array.Sort(lotto);
            Console.WriteLine("Your Lotto Numbers are:");
            for (int i = 0; i < lotto.Length; i  )
                Console.WriteLine(lotto[i]);
            Console.ReadLine();
        }

I tried using a while loop but the variables "line1" and "line2" as seen here Generating 2 Random Numbers that are Different C# but kept generating errors as

CodePudding user response：

Let's shuffle 1 .. 46 numbers and take 6 of them (in order to avoid duplicates). Then we can Join these taken numbers to show on the console:

using System.Linq;

...

// Simplest, but not thread safe
// use Random.Shared if your c# version supports it
private static readonly Random random = new Random();

...

public static void LottoDraw() 
{
    var lotto = Enumerable
      .Range(1, 46)
      .OrderBy(_ => random.Shared.NextDouble())  
      .Take(6)
      .OrderBy(item => item)
      .ToArray();

    Console.WriteLine(string.Join(Environment.NewLine, lotto));

    Console.ReadLine();    
}

Fiddle

CodePudding user response：

Lets write a method which creates lotto sets:

public static List<int> GenerateLottoSet(int n)
{
    var random = new Random();
    return Enumerable.Range(0, n).Select(_ => random.Next(1, 47)).ToList();
}

and then call it as many times as you need:

var set1 = GenerateLottoSet(6);
var set2 = GenerateLottoSet(6);