Regular Expression to match a sentence which induces a word with specific suffix and defined end wor-CodePudding

I'm trying to match a sentence which includes a word with a certain suffix and a specific word at the end.
For example sentence template would be;
"word word word (doesn't matter how many words before) wordSUFFIX thatspecificword."

I have tried this but could not match the words in the beginning.

(\w )(SUFFIX)\s thatspEcificword(suffix)?

CodePudding user response：

This should work:

Regex

.*(\b.*SUFFIX\b).*(specificword)$

See demo

Explanation

.* - search for zero or more characters of any type
(\b.*SUFFIX\b) - search for a word ending with SUFFIX
(specificword)$ - search for a "specificword" at the end of sentence.

Note:

If you cannot have matches where the entire word is SUFFIX, then you will need to change the regex to:

.*(\b. SUFFIX\b).*(specificword)$

The . ensures that there is at least one character before the SUFFIX

CodePudding user response：

As question tags are related to python, will try to answer from pythonic view.

If you simply want string ending with SUFFIX thatspecificword, then you may simply code like below -

pattern = "SUFFIX thatspecificword"
s = "word word word (doesn't matter how many words before) wordSUFFIX thatspecificword"
if s.endswith(pattern):
    print("match found")
else:
    print("match not found")

But if you want the string ending with wordSUFFIX thatspecificword where word can be any word i.e SUFFIX must be a word suffix then you might have a look into python built-in package named re which deals with regular expression -

import re

pattern = "\wSUFFIX thatspecificword$"
s = "word word word (doesn't matter how many words before) wordSUFFIX thatspecificword"
if re.search(pattern, s):
    print("match found")
else:
    print("match not found")