#include
The main ()
{
Int I=- 20;
Unsigned j=10;
Printf (" % d ", I + j).
Cout
CodePudding user response:
Int I=- 20;Unsigned j=10;
I + j//signed and unsigned number, returns the unsigned number
% d force output a signed integer
Cout
The original poster is not notice signed and unsigned number difference,
CodePudding user response:
I also old, educated,