I watched Ben Eater's video about building a computer based on 6502 chip and I'm stuck in part 3 (Assembly language VS Machine code). He is programming 32k EEPROM and he programmed by assembly to blink LED. This is assembler he used
But I have a question about org
directive, this is what I understand org tell assembler what address to start right?
In picture org
equals $8000
so I think first address instruction should be 8000
but when he output file it equal 0000
.
Why is the first instruction's address not 8000
?
CodePudding user response:
It's a flat binary with no metadata, and hexdump
is showing you file offsets anyway, not looking for metadata to figure out load addresses.
If you use xxd
to do the hex dumping, it has a -o
option that lets you specify an offset to add to the file position. xxd -g 1 -o 0x8000 a.out
should start at 00008000
and generally resemble hexdump -C
(1-byte groups, -groupsize 1
)
Disassemblers for flat binaries typically have similar options, to disassemble as if the image was loaded / mapped to a certain base address in memory.