CodePudding user response:

First is a integer to integer with % 0 f output is possible,

In addition, a=1.0/3 * 3; Because a is integer, 1.0/3 * 3 results may be 0.999 XXXX; So again into integer number is 0,

Modified method:

Float a;//define a type to float
Try ~

CodePudding user response:

double a;

CodePudding user response:

Line 4 code:
int a;
Modified into
Float a;
This will be the original data type for the integer data, a modified to and support the significant figures for at least six single precision floating point data of decimal places a
To accommodate the 5 results

CodePudding user response:

reference Cardistalive reply: 3/f

to line 4:
int a;
Modified into
Float a;
This will be the original data type for the integer data, a modified to and support the significant figures for at least six single precision floating point data of decimal places a
To accommodate the 5 results

Support effective Numbers for at least six single precision floating point data