One liner for comparing by property and returning a stream?-CodePudding

Is it possible to sort and return a stream in one line as in the following?

//@Getter..
public List<Actor> actors;

public Stream<Actor> actors() {
    //can these two lines be combined somehow?
    actors.sort(Comparator.comparing(Actor::getName));
    return actors.stream();
}

CodePudding user response：

you can do it like this:

return actors.stream().sorted(Comparator.comparing(Actor::getName));

The sort Method of a List will return void, so there is no chance to concat.

Greetings

CodePudding user response：

Streams has a sorted method

actors.stream().sorted(Comparator.comparing(Actor::getName))

Note: This will not sort the List. And will only sort the returned stream.