How to read array of integers from file and store it in array-CodePudding

I stored array to file with:

file = open("file1.txt", "w ")
 
    # Saving the 2D array in a text file
    content = array2d
    file.write(str(content))
    file.close()

and now I have to use that array that looks like this in file (this is just shorten):

[[[ 253  122]
  [ 253  121]
  [ 253  121]
  ...
  [1027  119]
  [1027  120]
  [1028  120]]

 [[ 252  122]
  [ 253  122]
  [ 253  122]
  ...
  
  [1067  573]
  [1067  573]
  [1067  573]]]

I have to open this file and store array in new one to access all integer elements like I can before saving.

I tried with:

text_file = open("file1.txt", "r")
data = []
data = text_file.read()

text_file.close()

print(data[0])

and as first element data[0] gives me [ and it should be 253.

CodePudding user response：

It gives you "[" because it is purely a text file, thus the first character of the string-array is just "[". I would suggest using numpy.save for saving arrays: https://numpy.org/doc/stable/reference/generated/numpy.save.html and numpy.load for loading arrays: https://numpy.org/doc/stable/reference/generated/numpy.load.html

Simply, numpy.save('name_of_file_to_save', array_to_save) And to load: numpy.load('name_of_file_to_save')

CodePudding user response：

Simple way using pickle

import pickle

file =  open("file1.txt", "wb") #file

content = [[[ 253 , 122],[ 253 , 121],[1067  ,573]]]
pickle.dump(content,  file) #saving
file.close()

file =  open("file1.txt", "rb") #file
data= pickle.load(file) #loadinga file
file.close()

print(data[0]) #e.x