#include
#include
#include
using namespace std;
Double eval (string) e
{stack
Double k, t, sum;
Int I=e.s considering (), j;
for(j=0; J
{t=s.t op ();
s.pop();
K=s.t op ();
s.pop();
If (e [j]=='+') sum=k + t;
If (e [j]=='-') sum=k - t;
If (e [j]=='*') sum=k * t;
If (e [j]=='/') sum=k/t;
Supachai panitchpakdi ush (sum);
}
The else supachai panitchpakdi ush ((double) (e) [j] - 96));
}
Return s.t op ();
}
Int main ()
{int num.
A string of AD;
cin> Num.
for(int i=0; i
cout
return 0;
}
Above is the program, some small problems, in the main input statement cin> Num. There is a problem, as long as I removed that line, to num assignment, program that's right, but once I use cin, program error, please answer
CodePudding user response:
Why no one reply, please answer
CodePudding user response:
Int main (){
int num;
A string of AD;
cin> Num.
for(int i=0; i
Getline (cin, AD);
cout
return 0;
}
Such as you enter 3 + 5-2, num take first character 3, go to the statements (for (int I=0; i
CodePudding user response:
Int main (){
int num;
A string of AD;
cin> Num.
getchar();//intercept enter
for(int i=0; i
Getline (cin, AD);
cout
return 0;
}
Double eval (string) e
{stack
Double k, t, sum;
Int I=e.s considering (), j;
for(j=0; J
{t=s.t op ();
s.pop();
K=e [j + 1);
//k=s.t op ();//shielding
//supachai panitchpakdi op ();
If (e [j]=='+') sum=k + t;
If (e [j]=='-') sum=k - t;
If (e [j]=='*') sum=k * t;
If (e [j]=='/') sum=k/t;
Supachai panitchpakdi ush (sum);
}
The else supachai panitchpakdi ush ((double) (e) [j] - 96));
}
Return s.t op ();
}
CodePudding user response:
In theory, should have no problem, if pressed key input, there is a problem, before the execution cycle you can put the value of num, print it out and see if the input is the same with you