X=x++;
System. The out. Println (x);
Output 1
CodePudding user response:
I++, after use the add first; + + I, since the first add after use; , you can do several ways to understand more about how to run a few times to understand, no tangle, you can read more in the case, should have to explain that, after all, textbooks are fond of speaking like a book, it is very suitable for speaking like a book,CodePudding user response:
First calculate=on the right side of the value of the expression, x++ first take the value of x 0 as the value of the expression, since then x increase to 1, and then assign the value of the expression 0 to x, so eventually x is 0CodePudding user response:
Hadn't been aware of the initial value is 1 xX++ first take the value of x 1 as the value of the expression, then the increase to 2 x, and then assign the value of the expression 1 to the left of the=x, so eventually x is 1