Given two lists, how to create a unique combinations and the elements in each combination are differ-CodePudding

Inputs:

list1 = ['Town1','Town2','Town3','Town4','Town5']

list2 = ['Town1','Town2','Town3','Town4','Town5']

Outputs:

[('Town1', 'Town2'), ('Town3', 'Town4'), ('Town4', 'Town4'), ('Town4', 'Town5'), ('Town1', 'Town4'), ('Town3', 'Town5'), ('Town1', 'Town3'), ('Town2', 'Town4'), ('Town1', 'Town5'), ('Town2', 'Town3'), ('Town2', 'Town5')]

I tried :

comb = list(product(list1,list2))
comb1 = [sorted(item) for item in comb]
comb2 = list(set(map(tuple,comb1)))

But ('Town1', 'Town1') is involved in the result.

CodePudding user response：

You can exclude the pairs with repeated elements with a list comprehension:

from itertools import product

list1 = ['Town1','Town2','Town3','Town4','Town5']

list2 = ['Town1','Town2','Town3','Town4','Town5']

comb = [pair for pair in product(list1,list2) if pair[0] != pair[1]]
print(comb)

The output is:

[('Town1', 'Town2'), ('Town1', 'Town3'), ('Town1', 'Town4'), ('Town1', 'Town5'), ('Town2', 'Town1'), ('Town2', 'Town3'), ('Town2', 'Town4'), ('Town2', 'Town5'), ('Town3', 'Town1'), ('Town3', 'Town2'), ('Town3', 'Town4'), ('Town3', 'Town5'), ('Town4', 'Town1'), ('Town4', 'Town2'), ('Town4', 'Town3'), ('Town4', 'Town5'), ('Town5', 'Town1'), ('Town5', 'Town2'), ('Town5', 'Town3'), ('Town5', 'Town4')]

CodePudding user response：

list1 = ['Town1','Town2','Town3','Town4','Town5']
list2 = ['Town1','Town2','Town3','Town4','Town5']

result = []

for i in list1:
    for j in list2:
        if i != j:
            result.append((i, j))

print(result)