* * (ptr1 + x 3)=(* + x * 3) (PTR) | (* + x * 3 + 1) (PTR) | (* (PTR + x * 3 + 2)); Why not

CodePudding user response:

What's not?
| is the bitwise or, & amp; Is the bitwise and

CodePudding user response:

And the operator is & amp;

CodePudding user response:

refer to the second floor sunxingzhesun response:

and operator is & amp; amp;

you or operation that is

CodePudding user response:

Agree to 1 on the second floor

CodePudding user response: