Why, what did free-CodePudding

 # include & lt; stdio.h> 
#include 
Int main () 
{
Int * p; 
//p=(int *) malloc (sizeof (int)); 
* p=5; 
Printf (" % p % d \ n, p, * p). 

//free (p); 
//* p=6; 

//printf (" % p % d \ n, p, * p). 

return 0; 
}

P no initialization, there is no any output
While the program execution to get reasonable results

 # include & lt; stdio.h> 
#include 
Int main () 
{
Int * p; 
P=(int *) malloc (sizeof (int)); 
* p=5; 
Printf (" % p % d \ n, p, * p). 

Free (p); 
//* p=6; 

Printf (" % p % d \ n, p, * p). 

return 0; 
} 

0 x55e7822282a0 5 
0 x55e7822282a0 0

But why did the following procedure to release the application memory * P will be assignment 6?

 # include & lt; stdio.h> 
#include 
Int main () 
{
Int * p; 
P=(int *) malloc (sizeof (int)); 
* p=5; 
Printf (" % p % d \ n, p, * p). 

Free (p); 
* p=6; 

Printf (" % p % d \ n, p, * p). 

return 0; 
} 

0 x55e5857e22a0 5 
0 x55e5857e22a0 6