write for the first time on this problem is a freshman just learning c + +, found that don't always have a testing point the code below

 # include 
using namespace std; 
Struct Inf//declare a structure array 
{
Char cid [19]. 
Int id [18]; 
Int amn. 
Int flag=1; 
} num [101]. 
Int main () {
Char box [11]={' 1 ', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'}; 
Int n, flag2=1; 
Cin & gt;> n; 
for (int i=0; i {
for (int j=0; J & lt; 18; J++) 
{
Cin & gt;> Num [I]. Cid [j]; 
If (num [I]. Cid [j]=='0') 
{
Num [I]. Id [j]=0; 
} 
Else if (num [I]. Cid [j]=='1') 
{
Num [I]. Id [j]=1; 
} 
Else if (num [I]. Cid [j]=='2') 
{
Num [I]. Id [j]=2; 
} 
Else if (num [I]. Cid [j]=='3') 
{
Num [I]. Id [j]=3; 
} 
Else if (num [I]. Cid [j]=='4') 
{
Num [I]. Id [j]=4; 
} 
Else if (num [I]. Cid [j]=='5') 
{
Num [I]. Id [j]=5; 
} 
Else if (num [I]. Cid [j]=='6') 
{
Num [I]. Id [j]=6; 
} 
Else if (num [I]. Cid [j]=='7') 
{
Num [I]. Id [j]=7; 
} 
Else if (num [I]. Cid [j]=='8') 
{
Num [I]. Id [j]=8; 
} 
Else if (num [I]. Cid [j]=='9') 
{
Num [I]. Id [j]=9; 
} 
Else if (num [I]. Cid [17]=='X') 
{
Num [I]. Id [j]=10; 
} 
} 
} 
for (int i=0; i {
Num [I]. Amn=((num [I] id [0]) * 7 + (num [I] id [1]) * 9 + (num [I] id [2]) * 10 + 
(num [I] id [3]) * 5 + (num [I] id [4]) * 8 + (num [I] id [5]) * 4 + 
(num [I] id [6]) * 2 + (num [I] id [7]) * 1 + (num [I] id [8]) * 6 + 
(num [I] id [9]) * 3 + (num [I] id [10]) * 7 + (num [I] id [11]) * 9 + 
(num [I] id [12]) * 10 + (num [I] id [13]) * 5 + (num [I] id [14]) * 8 + 
(num [I] id [15]) * 4 + (num [I] id [16]) * 2) % 11; 
} 
for (int i=0; i {
for (int j=0; J & lt; 17. J++) 
{
The switch (num [I] id [j]) 
{
Case 0: break; 
Case 1: break; 
Case 2: break; 
Case 3: break; 
Case 4: break; 
Case 5: break; 
Case 6: break; 
Case 7: break; 
Case 8: break; 
Case 9: break; 
Default: {the for (int o=0; O & lt; 18; O++) 17 before//will not output digital ID of the 
{
Cout & lt; } 
Cout & lt; Num [I] flag=0; 
Flag2=0; 
break; } 
} 
} 
If ((box [num [I] amn]! Num=[I]. Cid [17]) & amp; & Num [I] flag!=0) 
{
for (int j=0; J & lt; 18; J++) 
{
Cout & lt; Flag2=0; 
} 
Cout & lt; } 
} 
If (flag2==1) 
{
Cout & lt; <"All passed"; 
} 
return 0; 
} 

was bloated,,,,
Now a sophomore practice topic to write again after the found 15 points, now code below

 # include 
using namespace std; 
Int main () {
Int n, flag2=0; 
Int quan [17]={7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2}; 
Char code [11]={' 1 ', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'}; 
String id; 
Cin & gt;> n; 
getchar(); 
for (int i=0; i {
Int flag1=0, z=0;//xianhou 
Getline (cin, id); 
for (int j=0; J & lt; 17.//panduanqian17wei j++) 
{
If (id [j] <'0' | | id [j] & gt; '9') 
{
Cout & lt; Flag1=1; 
Flag2=1; 
} 
} 
If (flag1==0) 
{
for (int j=0; J & lt; 17. J++) 
{
Z +=(id [j] - '0') * quan [j]; 
} 
Z=z % 11; 
If (id [17]!=code [z]) 
{
Cout & lt; Flag2=1; 
} 
} 
} 
If (flag2==0) 
{
Cout & lt; <"All passed"; 
} 
return 0; 
} 

But as written before the code is so bad, cause he has been to find out why not 15 points, so in the BBS for help you,