How to use the most simple for loop to achieve
The effect of the need to achieve:

1, 2, 3, 4, 5
2, 3, 4, 5 1
3 4 5 1 2
4 5 1 2 3
1 2 3 4 5
(can't use arrays)

CodePudding user response:

 
Int nCount=5; 
For (int I=0; I & lt; NCount; + + I) 
{
for (int j=0; J & lt; NCount; + + j) 
{
Int nOutput=(I + j) % (nCount) + 1; 
Printf (" % d ", nOutput); 
} 

Printf (" \ r \ n "); 
} 

CodePudding user response:

So:

 
#include  

Int main () 
{
int i; 
int j; 
for (j=1; J<6; J++) 
{
For (I=j; i{
If (I & lt; 6) 
Printf (" % d ", I); 
The else 
Printf (" % d ", I % 5); 
printf(" "); 
} 
printf("\n"); 
} 
return 0; 
} 

CodePudding user response:

reference 1st floor Minikinfish response:

 
Int nCount=5; 
For (int I=0; I & lt; NCount; + + I) 
{
for (int j=0; J & lt; NCount; + + j) 
{
Int nOutput=(I + j) % (nCount) + 1; 
Printf (" % d ", nOutput); 
} 

Printf (" \ r \ n "); 
} 

Thank you, thank you very much, and don't thank gifts

CodePudding user response:

reference 1st floor Minikinfish response:

 
Int nCount=5; 
For (int I=0; I & lt; NCount; + + I) 
{
for (int j=0; J & lt; NCount; + + j) 
{
Int nOutput=(I + j) % (nCount) + 1; 
Printf (" % d ", nOutput); 
} 

Printf (" \ r \ n "); 
} 

Thank you, thank you