Master to help have a look at FC, 6 d, 0 d, 74, F6, of which 74, F6 is double check, data is FC, 6 d, 0 d, such as data EC again, BB, 11, 2 B, D9, among them 2 B, D9 is double check code, data is EC, BB, 11 the master to help work it out, and the calculation method of check code thank thank

CodePudding user response:

The data on the chart is the same calibration method

CodePudding user response:

CRC - 16/CCITT - FALSE (x16 + x12 + x 5 + 1)

http://www.ip33.com/crc.html

CodePudding user response:

CodePudding user response:

References from algorithm: https://www.cnblogs.com/yf142857/p/7245758.html

 
The function CRC16_CCITT_0xFFFF (Bytes: TBytes) : Word; 
Const 
Polynomial=$1021; 
Var 
CRC: Word; 
I, J: Integer; 
B: a Byte; 
Bit, C15: Boolean; 
The begin 
CRC:=$FFFF;//initial value 
For I:=0 to High (Bytes) do 
The begin 
B:=Bytes [I]; 
For J:=0 to 7 do 
The begin 
Bit:=(((B SHR (7 - J)) and 1)=1); 
C15:=(SHR CRC (15) and (1)=1); 
The CRC: CRC SHL=1; 
If (C15 xor Bit) then CRC:=CRC xor Polynomial; 
end; 
end; 
Result:=CRC and $FFFF; 
end; 

Procedure TForm1. FormCreate (Sender: TObject); 
Const 
Data: TBytes=[$FC, $6 d, $0 d]; 
Var 
CRC: Word; 
HexStr: AnsiString; 
The begin 
The CRC: CRC16_CCITT_0xFFFF=(Data); 
SetLength (HexStr, 4); 
BinToHex (@ CRC, PAnsiChar (HexStr), 4); 
ShowMessage (String (HexStr)); 
end; 

CodePudding user response:

refer to the second floor BlueStorm response:

CRC - 16/CCITT - FALSE (x16 + x12 + x 5 + 1)

http://www.ip33.com/crc.html

Thank you thank you, help me to solve the problem finally