The C language-CodePudding

Write a program to find the sum of consecutive integers is 500 all integer sequences,

CodePudding user response:

For reference only, the code is as follows:

 # include & lt; stdio.h> 

Int main (void) 
{
int i, j; 

for(i=1; i<=500; I++) 
{
/* consecutive number is odd number */
If (I % 2==1) 
{
If (500% I!=0) continue; 

Printf (" % d: \ t ", I); 
For (j=500/I - I/2; j<=500/I + I/2; J++) 
{
Printf (" % 5 d, j); 
} 
} 
/* consecutive number is odd number */
The else 
{
If (500% I!=I/2) continue; 

Printf (" % d: \ t ", I); 
For (j=500/I - I - 1)/2; j<=500/I + I/2; J++) 
{
Printf (" % 5 d, j); 
} 
} 
printf("\n"); 
} 
}

The results
500

 1:5:98 99 100 101 102 
8:59, 60, 61, 62, 63, 64, 65, 66 
25:8 9 10 11 12 13 14 15 16 17 18 19 20, 21, 22, 23 24 25, 26 and 27, 28 and 30, 31 and 32 
40:6-7-4-3-2-1-5-0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21, 22, 23 24 25, 26 and 27, 28 and 30, 31 and 32 
125:      -58  -57  -56  -55  -54  -53  -52  -51  -50  -49  -48  -47  -46  -45  -44  -43  -42  -41  -40  -39  -38  -37  -36  -35  -34  -33  -32  -31  -30  -29  -28  -27  -26  -25  -24  -23  -22  -21  -20  -19  -18  -17  -16  -15  -14  -13  -12  -11  -10   -9   -8   -7   -6   -5   -4   -3   -2   -1    0    1    2    3    4    5    6    7    8    9   10   11   12   13   14   15   16   17   18   19   20   21   22   23   24   25   26   27   28   29   30   31   32   33   34   35   36   37   38   39   40   41   42   43   44   45   46   47   48   49   50   51   52   53   54   55   56   57   58   59   60   61   62   63   64   65   66
200:      -97  -96  -95  -94  -93  -92  -91  -90  -89  -88  -87  -86  -85  -84  -83  -82  -81  -80  -79  -78  -77  -76  -75  -74  -73  -72  -71  -70  -69  -68  -67  -66  -65  -64  -63  -62  -61  -60  -59  -58  -57  -56  -55  -54  -53  -52  -51  -50  -49  -48  -47  -46  -45  -44  -43  -42  -41  -40  -39  -38  -37  -36  -35  -34  -33  -32  -31  -30  -29  -28  -27  -26  -25  -24  -23  -22  -21  -20  -19  -18  -17  -16  -15  -14  -13  -12  -11  -10   -9   -8   -7   -6   -5   -4   -3   -2   -1    0    1    2    3    4    5    6    7    8    9   10   11   12   13   14   15   16   17   18   19   20   21   22   23   24   25   26   27   28   29   30   31   32   33   34   35   36   37   38   39   40   41   42   43   44   45   46   47   48   49   50   51   52   53   54   55   56   57   58   59   60   61   62   63   64   65   66   67   68   69   70   71   72   73   74   75   76   77   78   79   80   81   82   83   84   85   86   87   88   89   90   91   92   93   94   95   96   97   98   99  100  101  102

CodePudding user response:

Hello lazy oh...

CodePudding user response:

refer to the original poster weixin_52516354 response:

program, find out all the integer sequence, the sum of consecutive integers is 500

There is no limit, so too much

CodePudding user response:

For 500, and then the first number must be smaller than 250

For (int first=0; First & lt; 250; First++)
{
.
}
For each first and then add in a row, until & gt;=500
Finally, judgment, and is it 500,
If it is, you are successful
If not, the next first
This code will write their own

Industrious, good,

CodePudding user response:

reference ctrigger reply: 3/f

are for reference only, the code is as follows:

 # include & lt; stdio.h> 

Int main (void) 
{
int i, j; 

for(i=1; i<=500; I++) 
{
/* consecutive number is odd number */
If (I % 2==1) 
{
If (500% I!=0) continue; 

Printf (" % d: \ t ", I); 
For (j=500/I - I/2; j<=500/I + I/2; J++) 
{
Printf (" % 5 d, j); 
} 
} 
/* consecutive number is odd number */
The else 
{
If (500% I!=I/2) continue; 

Printf (" % d: \ t ", I); 
For (j=500/I - I - 1)/2; j<=500/I + I/2; J++) 
{
Printf (" % 5 d, j); 
} 
} 
printf("\n"); 
} 
}

The results
500

 1:5:98 99 100 101 102 
8:59, 60, 61, 62, 63, 64, 65, 66 
25:8 9 10 11 12 13 14 15 16 17 18 19 20, 21, 22, 23 24 25, 26 and 27, 28 and 30, 31 and 32 
40:6-7-4-3-2-1-5-0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21, 22, 23 24 25, 26 and 27, 28 and 30, 31 and 32 
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