CodePudding user response:

Space with a const char * said, "" is a string, you can use the string. The data () method will turn const char * string

CodePudding user response:

Are there

 # include & lt; String. H> 

CodePudding user response:

 # include 
#include 
Int main (void) 
{
Char input [16]=ABC, "" d"; 
Char * p; 
/* strtok places a NULL terminator 
Infront of the token, if found */
P=strtok (input, ", "); 
If (p) 
Printf (" % s \ n ", p); 
/* Asecond call to strtok using a NULL 
As the first parameter returns a pointer 
To the character following the token */
P=strtok (NULL, ", "); 
If (p) 
Printf (" % s \ n ", p); 
return 0; 
} 

 # include 
#include 
using namespace std; 
Int main () 
{
Char sentence []="This is a sentence with 7 tokens". 
cout <"The string to be tokenized is: \ n" & lt; Char * tokenPtr=strtok (sentence, ""); 
While (tokenPtr!=NULL) {
CoutTokenPtr=strtok (NULL, ""); 
} 
//cout & lt; <"After the strtok, sentence=" & lt; return 0; 
} 

Baidu encyclopedia of the above two examples, code compared with you, to see what was missing

CodePudding user response:

refer to the second floor MianHou response:

are there

 # include & lt; String. H> 

Positive solution

CodePudding user response:

Thanks for your help