Virtual base class that shows the constructor of why its derived class members of the derived class-CodePudding

#include
using namespace std;
The class base0 {
Public:
Base0 (int I) : var0 (I) {}

Int var0;
Void fun0 () {
Cout<& lt;" Member of base0 "& lt; };
The class base1: virtual public base0 {
Public:
Base1 (int x) : base0 (x) {}
};
The class base2: virtual public base0 {
Public:
Base2 (int y) : base0 (y) {}
};
The class derived: public base1, public base2 {
Public:
Derived (int x, int y, int z) : base1 (x), base2 (y) and var (z) {}//this error to invoke base0 default constructor

Int var.
Void fun () {cout<& lt;" Member of the derived "& lt; };
Int main () {
Derived a (1, 2, 3);
A.f un0 ();

return 0;
}
When creating a derived object has joined the already give base0 constructor spread constructed base0 object is what to call it the default