Demand, modify the following code, starting from 0 x1020 output in turn,

CodePudding user response:

Don't change the loop condition is ok?

 for (I=n - 1; I & gt;=0; I -) {
Printf (" % # x \ t ", * (p + I)); 
} 

CodePudding user response:

Thank you, seem to be no through

The

reference 1/f, confident boy reply:

don't change the loop condition is ok?

 for (I=n - 1; I & gt;=0; I -) {
Printf (" % # x \ t ", * (p + I)); 
}