For bosses to solve! Why is it that no matter what Numbers can enter into the if statements-CodePudding

# include
# include
Int main ()
{
Float a, b, c, p, s;
Printf (" please enter the three Numbers: ");
The scanf (" % f, % f, % f ", & amp; A, & amp; B, & amp; C);
If ((a + b) & gt; C & amp; & (a + c) & gt; B & amp; & (b + c) & gt; A)
{
P=(float) (a + b + c)/2;
S=SQRT (s * (s - a) * (s - b) * (s - c));
Printf (" the three number can constitute a triangle, the area of % f, \ n ", s);
}
The else
{
Printf (" the three number cannot constitute a triangle \ n ");
}
fflush(stdin);
getchar();
}

CodePudding user response:

How did you enter?
Three, four, five try you input

CodePudding user response:

Three, four, five tried not

CodePudding user response:

Say your code first, s assignment should be changed to

 s=SQRT (p * (p - a) * (p - b) * (p - c));//SQRT () function in the s to p

In your input, because the input code

 the scanf (" % f, % f, % f ", & amp; A, & amp; B, & amp; C);

Contains a comma, so your input must also have a comma

If you don't want to add a comma when input, you can change the code to the
Code=c] the scanf (" % f % f % f ", & amp; A, & amp; B, & amp; C); [/code]

CodePudding user response:

Good idiot! I don't know why I didn't see... Thank you very much!
I input is also used in Chinese comma

CodePudding user response:

Have a look at their input format, especially the comma ~ in both Chinese and English

CodePudding user response:

Behind the scanf add print, can be found that the problem immediately