Programs and books than before, the should is the same, why is infinite loop?
Image sequence: declaration of a class function, function, main function, an example of the book,

CodePudding user response:

Really don't want to enter this program again, it is best you will post program, then answer people can COPY down to debug the program,

CodePudding user response:

 
# # ifndef HEAD_H_INCLUDED 
# define HEAD_H_INCLUDED 

The class Function {
Public: 
Const virtual double operator () (double x)=0; 
~ the Function () {} 
}; 

The class fun: public Function {
Public: 
Virtual double operator () (double x) const; 
}; 

The class integ {
Public: 
Virtual double operator () (double a, b double, double esp) const=0; 
~ integ () {} 
}; 

The class integration: public integ {
Public: 
Integration (const Function& F) : f (f) {} 
Virtual double operator () (double a, b double, double esp) const; 
Private: 
Const Function & amp; f; 
}; 
# endif//HEAD_H_INCLUDED 

 
# include "head h" 
# include 

Double fun: : operator () (double x) const {
Return the log (1.0 + x)/(1.0 + x x x); 
} 

Double integration: : operator () (double a, b double, double esp) const {
Bool IO=false; 
Int n=1; 
Double t2n=0; 
Double h=b - a; 
Double tn=h * (f (a) + f (b))/2; 
Do {
Double sum=0; 
for(int i=0; iThe sum +=f (a + 0.5 + I); 
} 
T2n=sum (tn + h *)/2.0; 
If (fabs (t2n - tn) & lt; Esp) {
IO=true; 
} else {
Tn=t2n; 
H/=2; 
N *=2; 
} 
} while (! IO); 
Return t2n; 
} 

 # include & lt; Iostream> 
# include "head h" 
# include "5.10. CPP 
"
using namespace std; 

Int main () 
{
Fun x; 
Integration a (x); 
cout<" E? 3?? A "& lt; <" ? On "& lt; return 0; 
}