CodePudding user response:

 # include 
Int main () {

Int a [100 + 1)={0}, n=0, I, c, t; 
Printf (" please input array length: \ n "); 
The scanf (" % d ", & amp; n); 
If (n<1 | | 100 & lt; N) {
Printf (" array length must be between 1 and 100 \ n "); 
return -1; 
} 
Printf (" please enter the Numbers in turn: \ n "); 
for(i=1; i<=n; I++) {
Printf (" \ na [% d]=", I); The fflush (stdout); 
The scanf (" % d ", & amp; A [I]); 
} 

For (c=1; CFor (I=c + 1; i<=n; I++) {
If (a [I] <+ 1=a [I]) {
T=a [I]; A [I]=a, [I + 1]. A [I + 1]=t; 
} 
} 
} 

for(i=1; i<=n; I++) {
Printf (" % d \ n ", a [I]); 
} 
return 0; 
} 

CodePudding user response:

reference 1/f, zhao teacher reply:

 # include 
Int main () {

Int a [100 + 1)={0}, n=0, I, c, t; 
Printf (" please input array length: \ n "); 
The scanf (" % d ", & amp; n); 
If (n<1 | | 100 & lt; N) {
Printf (" array length must be between 1 and 100 \ n "); 
return -1; 
} 
Printf (" please enter the Numbers in turn: \ n "); 
for(i=1; i<=n; I++) {
Printf (" \ na [% d]=", I); The fflush (stdout); 
The scanf (" % d ", & amp; A [I]); 
} 

For (c=1; CFor (I=c + 1; i<=n; I++) {
If (a [I] <+ 1=a [I]) {
T=a [I]; A [I]=a, [I + 1]. A [I + 1]=t; 
} 
} 
} 

for(i=1; i<=n; I++) {
Printf (" % d \ n ", a [I]); 
} 
return 0; 
} 

This value should not be an array can not define the length of the
This will be not check the overflow system problem?

CodePudding user response:

Int a []={0} can't define arrays oh must want to have a fixed length

CodePudding user response:

 # include 
Int main () {

Int * a, n=0, I, c, t; 
Printf (" please input array length: \ n "); 
The scanf (" % d ", & amp; n); 
If (n<1 | | 100000 & lt; N) {
Printf (" array length must be between 1 and 100000 \ n "); 
return -1; 
} 
A=new int [n + 1); 
Printf (" please enter the Numbers in turn: \ n "); 
for(i=1; i<=n; I++) {
Printf (" a [% d]=", I); The fflush (stdout); 
The scanf (" % d ", & amp; A [I]); 
} 

For (c=1; CFor (I=c + 1; i<=n; I++) {
If (a [c] T=a [c]; A [c]=a, [I]. A [I]=t; 
} 
} 
} 

for(i=1; i<=n; I++) {
Printf (" % d \ n ", a [I]); 
} 
The delete [] a; 
return 0; 
} 
//please input array length: 
//4 
//please enter the Numbers in turn: 
//a [1]=3 
//a [2]=9 
//a [3]=5 
//a [4]=2 
//9 
//5 
//3 
//2 
//

CodePudding user response:

quoted zhao 4, 4/f, the teacher's reply:

 # include 
Int main () {

Int * a, n=0, I, c, t; 
Printf (" please input array length: \ n "); 
The scanf (" % d ", & amp; n); 
If (n<1 | | 100000 & lt; N) {
Printf (" array length must be between 1 and 100000 \ n "); 
return -1; 
} 
A=new int [n + 1); 
Printf (" please enter the Numbers in turn: \ n "); 
for(i=1; i<=n; I++) {
Printf (" a [% d]=", I); The fflush (stdout); 
The scanf (" % d ", & amp; A [I]); 
} 

For (c=1; CFor (I=c + 1; i<=n; I++) {
If (a [c] T=a [c]; A [c]=a, [I]. A [I]=t; 
} 
} 
} 

for(i=1; i<=n; I++) {
Printf (" % d \ n ", a [I]); 
} 
The delete [] a; 
return 0; 
} 
//please input array length: 
//4 
//please enter the Numbers in turn: 
//a [1]=3 
//a [2]=9 
//a [3]=5 
//a [4]=2 
//9 
//5 
//3 
//2 
//

Probably understand, thank you! ??

CodePudding user response:

reference 3/f, 5250 response:

int a []={0} can't define arrays oh there must be a fixed length

But numerical array is not necessarily to define the length?

CodePudding user response:

Beg to write the code

CodePudding user response:

refer to 7th floor Zhi Zhao response:

beg to write the code

Ha ha 'new beginning??nullnullnullnull