Collect inside want to get a post reply paging

Such as 20 reply will turn on page 1, 40 reply will turn to the second page


Assuming that n is my reply to post total is 14

Assuming that M is my set how many reply will flip gathering here I set the 20

How to determine the logic to get him into

20=1
40=2
60=3
80=4

How to implement this logic, similar to the below divisible

 if (n % m==0) {
System. The out. Println (" n can be divided exactly by m "); 
} else {
System. The out. Println (" n can't be divided exactly by m "); 
} 

CodePudding user response:

Directly post/total number of pages per page down integer not equal to the page number

CodePudding user response:

Int page=n/(m + 1) + 1;

CodePudding user response:

Int page=n/m + (n % m==0)? 1-0.

CodePudding user response:

Int page=(n> 0? N - 1:0)/m + 1;

CodePudding user response:

Int page=(int) Math. Ceil (Double. The valueOf (n)/m); Take up the whole

CodePudding user response:

Int page=(m - 1)/(n) + 1