While ((a [I]=getchar ())! )
='\ n'{
i++;
}
And
While ([n] s) n++;
S/n * 2='\ 0';
n--;
While (n>=0) {
S/n * 2=s [n].
S [n * 2 + 1]=32;
n--;
What do you mean respectively

CodePudding user response:

First is to read the user input back to the front, endures a []