# include & lt; stdio.h>
Void Swap (int x, int y);
Int main ()
{
Int a, b;
Printf (" do enter a, b: ");
Scanf_s (" % d % d ", & amp; A, & amp; B);
Printf (" Before swap: a=% d, b=% d \ n ", a, b);
Swap (a, b);
Printf (" After swap: a=% d, b=% d \ n ", a, b);
return 0;
}
Void Swap (int x, int y)
{
int temp;
temp=x;
X=y;
Y=temp;
}
Why can't enter the function carried out ah?

CodePudding user response:

The value of C language, need to pass the address just have effect, only supplies the reference:

 # include & lt; stdio.h> 
Void Swap (int * x, int * y); 
Int main (void) 
{
Int a, b; 
Printf (" do enter a, b: "); 
Scanf_s (" % d % d ", & amp; A, & amp; B); 
Printf (" Before swap: a=% d, b=% d \ n ", a, b); 
Swap (& amp; A, & amp; B); 
Printf (" After swap: a=% d, b=% d \ n ", a, b); 
return 0; 
} 
Void Swap (int * x, int * y) 
{
int temp; 
Temp=* x; 
* x=* y; 
* y=temp; 
}