Campus oj topic question-CodePudding

C language beginner, why can't I write output?

CodePudding user response:

To this:

 while ((ch=getchar ())!='\ n')

If you use the

 while (ch=getchar ()!='\ n')

This ch is true or false

CodePudding user response:

Input is a string, not a single character, modified as follows, for reference:

 # include & lt; stdio.h> 
Int main (int arg c, char * argv []) 
{
Int vowel (char ch); 
Int x, sum=0, I=0; 
Char ch [80]. 
Gets (ch); 
While (ch [I]!='\ 0') {
If (vowel (ch) [I]) 
The sum +=1; 
i++; 
} 
Printf (" % d ", sum); 
system("pause"); 
return 0; 
} 

Int vowel (char ch) 
{
If (ch=='A' | | ch=='A' | | ch=='E' | | ch=='E' | | ch=='I' | | ch=='I' | | ch=='o' | | ch=='o') 
return 1; 
return 0; 
}

CodePudding user response:

While (ch=getchar ()! )
='\ n'
The following instead, give it a try:

reference

while ((ch=getchar ())!='\ n')

CodePudding user response:

This screen carbon baked?

CodePudding user response:

The

reference 1/f, confident boy reply:

change to this:
 while ((ch=getchar ())!='\ n') 
If you use the
 while (ch=getchar ()!='\ n') 
Ch is so true and false

thank you

CodePudding user response:

refer to the second floor QZJHJXJ response:

input string, not a single character, modified as follows, for reference:

 # include & lt; stdio.h> 
Int main (int arg c, char * argv []) 
{
Int vowel (char ch); 
Int x, sum=0, I=0; 
Char ch [80]. 
Gets (ch); 
While (ch [I]!='\ 0') {
If (vowel (ch) [I]) 
The sum +=1; 
i++; 
} 
Printf (" % d ", sum); 
system("pause"); 
return 0; 
} 

Int vowel (char ch) 
{
If (ch=='A' | | ch=='A' | | ch=='E' | | ch=='E' | | ch=='I' | | ch=='I' | | ch=='o' | | ch=='o') 
return 1; 
return 0; 
}

thank you

CodePudding user response:

The

reference 3 floor ctrigger response:

while (ch=getchar ()! )
='\ n'
The following instead, give it a try:

reference
while ((ch=getchar ())!='\ n')

thank you