CodePudding user response:
Oh I see be okayCodePudding user response:
A=a + b - a \ \ b=(a) the value of a, the first operation in bracketsB=a
But it really general, don't feel,
CodePudding user response:
This usage is the premise, is a + b should not exceed the scope of this type, or beyond the scope of cross-border turned negative, may not want to be the result of the