Problem: s=[j] a [I]; And s=[j] a [I]; The difference between-CodePudding

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Problem: s=[j] a [I]; And s=[j] a [I]; The difference between

Time：12-23

Hypothesis j=I=0,
The former: s [0]=a [0]
The latter: s [1] a [0]=
Is that so? Why is that?

Examples are shown in figure

CodePudding user response:

The building Lord understand, correct answer to choose A, A answer execution order is s [j] [I]=s; J + 1; , if it is [+ + j]=s a [I], execution order is j + 1; S [j] [I]=s; , so the rules,

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